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We Will Be Solving Problems In Real Life By Using The Methods Learned In Week

We Will Be Solving Problems In Real Life By Using The Methods Learned In Week

We Will Be Solving Problems In Real Life By Using The Methods Learned In Week

we will be solving problems in Real Life by using the methods learned in week 4 for solving systems of equations
Most everyone has a fear of word problems because you haven’t had much experience in solving them
If you just take them one step at a time, you will find them manageable and build your confidence in your ability to successfully tackle any word problem you meet
Remember: I am here to help you! Please read the prompt above to see additional instructions for your Initial Post
Here is an example to get us started
I am working out the entire problem for you, but in your initial post you only need to set up the situation and leave solving the problem to a classmate (see prompt given above)
APPLICATION PROBLEM: DISTANCE = RATE X TIME A boat’s crew rowed 12 miles downstream, with the current, in 1
5 hours
The return trip, against the current, covered the same distance but took 4 hours
Find the crews rowing rate in still water and the rate of the current
The relationship we need to use isDistance = Rate x Time
We will havetwoequations:one for the trip downstream and one for the trip upstream
We have two variables: crews rowing rate in still water and rate of the current
Letw = crews rowing rate in still water Letc = rate of the current Downstream: Distance = Rate xTime Rate will be w+c (rate in still water + current) (1) 12 = (w+c) 1
5 = 1
5w+1
5c Upstream: Distance = Rate xTime Rate will be w-c (rate in still water – current) (2) 12 = (w-c) 4 = 4w-4c One approach is tosimplifythe equations before solving the system
(1) 12=1
5w+1
5c divideboth sides by 1
5 8 = w + c (2) 12 = 4w=4cdivide both sides by 4 3 = w – c UseEliminationon the two equations 8 = w+c 3 = w-c After adding the two equations we have 11 = 2w divide by 2 w = 11/2 =5
5 Usethis value to solve for c
w+c = 8 5
5+c = 8 c = 8 – 5
5 c=2
5 Therefore, therate of the current is 2
5and therate of the crewrowing in still water is 5
5
I can’t wait to see your posts
You may use a scholarly resource, just remember to cite it